Base | Representation |
---|---|
bin | 10001111011101100100… |
… | …101111000101011101011 |
3 | 11100210212012022100000202 |
4 | 101323230211320223223 |
5 | 130142302440014011 |
6 | 2342042524422415 |
7 | 155014200115055 |
oct | 21735445705353 |
9 | 4323765270022 |
10 | 1232330001131 |
11 | 4356a0182499 |
12 | 17aa009a7a0b |
13 | 8c2925ca5a8 |
14 | 439061b08d5 |
15 | 220c816023b |
hex | 11eec978aeb |
1232330001131 has 4 divisors (see below), whose sum is σ = 1233116428992. Its totient is φ = 1231543573272.
The previous prime is 1232330001107. The next prime is 1232330001239. The reversal of 1232330001131 is 1311000332321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1232330001131 - 210 = 1232330000107 is a prime.
It is a super-2 number, since 2×12323300011312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1232330001031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393211580 + ... + 393214713.
It is an arithmetic number, because the mean of its divisors is an integer number (308279107248).
Almost surely, 21232330001131 is an apocalyptic number.
1232330001131 is a deficient number, since it is larger than the sum of its proper divisors (786427861).
1232330001131 is an equidigital number, since it uses as much as digits as its factorization.
1232330001131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 786427860.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1232330001131 its reverse (1311000332321), we get a palindrome (2543330333452).
The spelling of 1232330001131 in words is "one trillion, two hundred thirty-two billion, three hundred thirty million, one thousand, one hundred thirty-one".
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