Base | Representation |
---|---|
bin | 1011001101010011111101… |
… | …0000000000010011111011 |
3 | 1121122002122112002101001212 |
4 | 2303110333100000103323 |
5 | 3103401131004114121 |
6 | 42113131153433335 |
7 | 2411221262336156 |
oct | 263247720002373 |
9 | 47562575071055 |
10 | 12323322332411 |
11 | 3a21323208692 |
12 | 147041386b84b |
13 | 6b51132c738c |
14 | 308648356c9d |
15 | 165857d6025b |
hex | b353f4004fb |
12323322332411 has 2 divisors, whose sum is σ = 12323322332412. Its totient is φ = 12323322332410.
The previous prime is 12323322332303. The next prime is 12323322332413. The reversal of 12323322332411 is 11423322332321.
12323322332411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12323322332411 - 222 = 12323318138107 is a prime.
Together with 12323322332413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12323322332413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161661166205 + 6161661166206.
It is an arithmetic number, because the mean of its divisors is an integer number (6161661166206).
Almost surely, 212323322332411 is an apocalyptic number.
12323322332411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12323322332411 is an equidigital number, since it uses as much as digits as its factorization.
12323322332411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31104, while the sum is 32.
Adding to 12323322332411 its reverse (11423322332321), we get a palindrome (23746644664732).
The spelling of 12323322332411 in words is "twelve trillion, three hundred twenty-three billion, three hundred twenty-two million, three hundred thirty-two thousand, four hundred eleven".
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