Base | Representation |
---|---|
bin | 1011001101010110101011… |
… | …0111100100101001010111 |
3 | 1121122011112112002021222101 |
4 | 2303111222313210221113 |
5 | 3103404130324001033 |
6 | 42113331534342531 |
7 | 2411245356433525 |
oct | 263255267445127 |
9 | 47564475067871 |
10 | 12324054125143 |
11 | 3a216692a2372 |
12 | 147059895aa47 |
13 | 6b51cbab8727 |
14 | 3086b7609315 |
15 | 16589c21297d |
hex | b356ade4a57 |
12324054125143 has 4 divisors (see below), whose sum is σ = 12472536705048. Its totient is φ = 12175571545240.
The previous prime is 12324054125111. The next prime is 12324054125237. The reversal of 12324054125143 is 34152145042321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12324054125143 - 25 = 12324054125111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12324054120143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74241289828 + ... + 74241289993.
It is an arithmetic number, because the mean of its divisors is an integer number (3118134176262).
Almost surely, 212324054125143 is an apocalyptic number.
12324054125143 is a deficient number, since it is larger than the sum of its proper divisors (148482579905).
12324054125143 is an equidigital number, since it uses as much as digits as its factorization.
12324054125143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148482579904.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 12324054125143 its reverse (34152145042321), we get a palindrome (46476199167464).
The spelling of 12324054125143 in words is "twelve trillion, three hundred twenty-four billion, fifty-four million, one hundred twenty-five thousand, one hundred forty-three".
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