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123241401115213 is a prime number
BaseRepresentation
bin11100000001011001011111…
…111011110110001001001101
3121011100202121010211120010111
4130001121133323312021031
5112123141342141141323
61114040152412040021
734646616544105123
oct3401313773661115
9534322533746114
10123241401115213
11362a542603a787
12119a5013a63011
13539c7ca6aa544
142260cb6737913
15e3abd1d1ac0d
hex70165fef624d

123241401115213 has 2 divisors, whose sum is σ = 123241401115214. Its totient is φ = 123241401115212.

The previous prime is 123241401115207. The next prime is 123241401115241. The reversal of 123241401115213 is 312511104142321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119606113585764 + 3635287529449 = 10936458^2 + 1906643^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123241401115213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123241401116213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61620700557606 + 61620700557607.

It is an arithmetic number, because the mean of its divisors is an integer number (61620700557607).

Almost surely, 2123241401115213 is an apocalyptic number.

It is an amenable number.

123241401115213 is a deficient number, since it is larger than the sum of its proper divisors (1).

123241401115213 is an equidigital number, since it uses as much as digits as its factorization.

123241401115213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 123241401115213 its reverse (312511104142321), we get a palindrome (435752505257534).

The spelling of 123241401115213 in words is "one hundred twenty-three trillion, two hundred forty-one billion, four hundred one million, one hundred fifteen thousand, two hundred thirteen".