Base | Representation |
---|---|
bin | 11100000001011010011101… |
… | …010010011101101010001011 |
3 | 121011100212020212201102001111 |
4 | 130001122131102131222023 |
5 | 112123200444144020121 |
6 | 1114040442502231151 |
7 | 34646654213253052 |
oct | 3401323522355213 |
9 | 534325225642044 |
10 | 123242430454411 |
11 | 362a5904082534 |
12 | 119a52607254b7 |
13 | 539c932a1a9a8 |
14 | 2260d73321399 |
15 | e3ac423952e1 |
hex | 70169d49da8b |
123242430454411 has 2 divisors, whose sum is σ = 123242430454412. Its totient is φ = 123242430454410.
The previous prime is 123242430454397. The next prime is 123242430454417. The reversal of 123242430454411 is 114454034242321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123242430454411 - 211 = 123242430452363 is a prime.
It is not a weakly prime, because it can be changed into another prime (123242430454417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61621215227205 + 61621215227206.
It is an arithmetic number, because the mean of its divisors is an integer number (61621215227206).
Almost surely, 2123242430454411 is an apocalyptic number.
123242430454411 is a deficient number, since it is larger than the sum of its proper divisors (1).
123242430454411 is an equidigital number, since it uses as much as digits as its factorization.
123242430454411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 368640, while the sum is 40.
Adding to 123242430454411 its reverse (114454034242321), we get a palindrome (237696464696732).
The spelling of 123242430454411 in words is "one hundred twenty-three trillion, two hundred forty-two billion, four hundred thirty million, four hundred fifty-four thousand, four hundred eleven".
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