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123243431145251 is a prime number
BaseRepresentation
bin11100000001011011011000…
…111011110010111100100011
3121011100221211121200202211012
4130001123120323302330203
5112123210021333122001
61114041130050411135
734650021054062054
oct3401333073627443
9534327747622735
10123243431145251
11362a6277a2835a
12119a549b890aab
13539ca6213a451
14226102a1ac72b
15e3aca01612bb
hex7016d8ef2f23

123243431145251 has 2 divisors, whose sum is σ = 123243431145252. Its totient is φ = 123243431145250.

The previous prime is 123243431145203. The next prime is 123243431145299. The reversal of 123243431145251 is 152541134342321.

It is a balanced prime because it is at equal distance from previous prime (123243431145203) and next prime (123243431145299).

It is a cyclic number.

It is not a de Polignac number, because 123243431145251 - 218 = 123243430883107 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123243431145199 and 123243431145208.

It is not a weakly prime, because it can be changed into another prime (123243431115251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61621715572625 + 61621715572626.

It is an arithmetic number, because the mean of its divisors is an integer number (61621715572626).

Almost surely, 2123243431145251 is an apocalyptic number.

123243431145251 is a deficient number, since it is larger than the sum of its proper divisors (1).

123243431145251 is an equidigital number, since it uses as much as digits as its factorization.

123243431145251 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 345600, while the sum is 41.

Adding to 123243431145251 its reverse (152541134342321), we get a palindrome (275784565487572).

The spelling of 123243431145251 in words is "one hundred twenty-three trillion, two hundred forty-three billion, four hundred thirty-one million, one hundred forty-five thousand, two hundred fifty-one".