Base | Representation |
---|---|
bin | 11100000001011011111011… |
… | …100000010110001111011111 |
3 | 121011101000100001002011222122 |
4 | 130001123323200112033133 |
5 | 112123212213323333401 |
6 | 1114041303410133155 |
7 | 34650041326051625 |
oct | 3401337340261737 |
9 | 534330301064878 |
10 | 123244011152351 |
11 | 362a6545370271 |
12 | 119a5621b811bb |
13 | 539cb25355c0b |
14 | 226108322d515 |
15 | e3acd603021b |
hex | 7016fb8163df |
123244011152351 has 2 divisors, whose sum is σ = 123244011152352. Its totient is φ = 123244011152350.
The previous prime is 123244011152323. The next prime is 123244011152369. The reversal of 123244011152351 is 153251110442321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123244011152351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123244011152371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61622005576175 + 61622005576176.
It is an arithmetic number, because the mean of its divisors is an integer number (61622005576176).
Almost surely, 2123244011152351 is an apocalyptic number.
123244011152351 is a deficient number, since it is larger than the sum of its proper divisors (1).
123244011152351 is an equidigital number, since it uses as much as digits as its factorization.
123244011152351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 123244011152351 its reverse (153251110442321), we get a palindrome (276495121594672).
The spelling of 123244011152351 in words is "one hundred twenty-three trillion, two hundred forty-four billion, eleven million, one hundred fifty-two thousand, three hundred fifty-one".
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