Base | Representation |
---|---|
bin | 11100000010010001011010… |
… | …000000111100010110110011 |
3 | 121011120111112202021110002022 |
4 | 130002101122000330112303 |
5 | 112130132312410031402 |
6 | 1114123521235542055 |
7 | 34654143261365213 |
oct | 3402213200742663 |
9 | 534514482243068 |
10 | 123301431330227 |
11 | 36318930584827 |
12 | 119b4787a5a92b |
13 | 53a5376486527 |
14 | 2263b6d214243 |
15 | e3c54703b2a2 |
hex | 70245a03c5b3 |
123301431330227 has 2 divisors, whose sum is σ = 123301431330228. Its totient is φ = 123301431330226.
The previous prime is 123301431330197. The next prime is 123301431330229. The reversal of 123301431330227 is 722033134103321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123301431330227 - 218 = 123301431068083 is a prime.
Together with 123301431330229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (123301431330229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61650715665113 + 61650715665114.
It is an arithmetic number, because the mean of its divisors is an integer number (61650715665114).
Almost surely, 2123301431330227 is an apocalyptic number.
123301431330227 is a deficient number, since it is larger than the sum of its proper divisors (1).
123301431330227 is an equidigital number, since it uses as much as digits as its factorization.
123301431330227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 123301431330227 its reverse (722033134103321), we get a palindrome (845334565433548).
The spelling of 123301431330227 in words is "one hundred twenty-three trillion, three hundred one billion, four hundred thirty-one million, three hundred thirty thousand, two hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •