Base | Representation |
---|---|
bin | 1011001101101101111111… |
… | …0111111110001011100101 |
3 | 1121122202200122121221120020 |
4 | 2303123133313332023211 |
5 | 3104004434401200201 |
6 | 42120244525225353 |
7 | 2411556425550453 |
oct | 263333767761345 |
9 | 47582618557506 |
10 | 12330312131301 |
11 | 3a2428a824a8a |
12 | 1471844702259 |
13 | 6b598846b058 |
14 | 308b0c7b99d3 |
15 | 165b16811a36 |
hex | b36dfdfe2e5 |
12330312131301 has 4 divisors (see below), whose sum is σ = 16440416175072. Its totient is φ = 8220208087532.
The previous prime is 12330312131299. The next prime is 12330312131369. The reversal of 12330312131301 is 10313121303321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12330312131301 - 21 = 12330312131299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12330312131101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2055052021881 + ... + 2055052021886.
It is an arithmetic number, because the mean of its divisors is an integer number (4110104043768).
Almost surely, 212330312131301 is an apocalyptic number.
It is an amenable number.
12330312131301 is a deficient number, since it is larger than the sum of its proper divisors (4110104043771).
12330312131301 is an equidigital number, since it uses as much as digits as its factorization.
12330312131301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4110104043770.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 12330312131301 its reverse (10313121303321), we get a palindrome (22643433434622).
The spelling of 12330312131301 in words is "twelve trillion, three hundred thirty billion, three hundred twelve million, one hundred thirty-one thousand, three hundred one".
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