Base | Representation |
---|---|
bin | 1011001101101110110101… |
… | …0110110100101001110111 |
3 | 1121122210021102020122121221 |
4 | 2303123231112310221313 |
5 | 3104010420302310201 |
6 | 42120323205251211 |
7 | 2411565143261251 |
oct | 263335526645167 |
9 | 47583242218557 |
10 | 12330538322551 |
11 | 3a243964768a9 |
12 | 14718a8403b07 |
13 | 6b59c3295827 |
14 | 308b30858cd1 |
15 | 165b2b5e14a1 |
hex | b36ed5b4a77 |
12330538322551 has 4 divisors (see below), whose sum is σ = 12330660821704. Its totient is φ = 12330415823400.
The previous prime is 12330538322497. The next prime is 12330538322593. The reversal of 12330538322551 is 15522383503321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12330538322551 - 27 = 12330538322423 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12330538322498 and 12330538322507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12330538322651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61098465 + ... + 61299946.
It is an arithmetic number, because the mean of its divisors is an integer number (3082665205426).
Almost surely, 212330538322551 is an apocalyptic number.
12330538322551 is a deficient number, since it is larger than the sum of its proper divisors (122499153).
12330538322551 is a wasteful number, since it uses less digits than its factorization.
12330538322551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122499152.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 12330538322551 in words is "twelve trillion, three hundred thirty billion, five hundred thirty-eight million, three hundred twenty-two thousand, five hundred fifty-one".
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