12331212601541 has 2 divisors, whose sum is σ = 12331212601542. Its totient is φ = 12331212601540.

The previous prime is 12331212601529. The next prime is 12331212601579. The reversal of 12331212601541 is 14510621213321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12279039189316 + 52173412225 = 3504146^2 + 228415^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12331212601541 is a prime.

It is a super-3 number, since 3×12331212601541³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12331212601498 and 12331212601507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12331212601441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165606300770 + 6165606300771.

It is an arithmetic number, because the mean of its divisors is an integer number (6165606300771).

Almost surely, 2^{12331212601541} is an apocalyptic number.

It is an amenable number.

12331212601541 is a deficient number, since it is larger than the sum of its proper divisors (1).

12331212601541 is an equidigital number, since it uses as much as digits as its factorization.

12331212601541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 12331212601541 its reverse (14510621213321), we get a palindrome (26841833814862).

The spelling of 12331212601541 in words is "twelve trillion, three hundred thirty-one billion, two hundred twelve million, six hundred one thousand, five hundred forty-one".