Base | Representation |
---|---|
bin | 11100000010011100010111… |
… | …011111010001111000011101 |
3 | 121011121121220221022110110121 |
4 | 130002130113133101320131 |
5 | 112130330413212024013 |
6 | 1114133145125434541 |
7 | 34655041024360624 |
oct | 3402342737217035 |
9 | 534547827273417 |
10 | 123313200111133 |
11 | 3632291a77003a |
12 | 119b6b1126ba51 |
13 | 53a6500752c06 |
14 | 22645682446bb |
15 | e3c9d533758d |
hex | 7027177d1e1d |
123313200111133 has 8 divisors (see below), whose sum is σ = 127580060935800. Its totient is φ = 119047318053888.
The previous prime is 123313200111121. The next prime is 123313200111151. The reversal of 123313200111133 is 331111002313321.
It can be written as a sum of positive squares in 4 ways, for example, as 59565702565924 + 63747497545209 = 7717882^2 + 7984203^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123313200111133 is a prime.
It is a super-2 number, since 2×1233132001111332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123313200111098 and 123313200111107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123313200111433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 244435516 + ... + 244939477.
It is an arithmetic number, because the mean of its divisors is an integer number (15947507616975).
Almost surely, 2123313200111133 is an apocalyptic number.
It is an amenable number.
123313200111133 is a deficient number, since it is larger than the sum of its proper divisors (4266860824667).
123313200111133 is an equidigital number, since it uses as much as digits as its factorization.
123313200111133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 489383711.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 123313200111133 its reverse (331111002313321), we get a palindrome (454424202424454).
The spelling of 123313200111133 in words is "one hundred twenty-three trillion, three hundred thirteen billion, two hundred million, one hundred eleven thousand, one hundred thirty-three".
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