Base | Representation |
---|---|
bin | 1011001101110001110010… |
… | …0111011101001101001111 |
3 | 1121122212022200012121121221 |
4 | 2303130130213131031033 |
5 | 3104014031242241421 |
6 | 42120534011504211 |
7 | 2411623611601522 |
oct | 263343447351517 |
9 | 47585280177557 |
10 | 12331331212111 |
11 | 3a24762aa052a |
12 | 1471a89a58067 |
13 | 6b5abb629152 |
14 | 308ba7c92bb9 |
15 | 165b76011841 |
hex | b371c9dd34f |
12331331212111 has 4 divisors (see below), whose sum is σ = 12756549529800. Its totient is φ = 11906112894424.
The previous prime is 12331331212093. The next prime is 12331331212117. The reversal of 12331331212111 is 11121213313321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12331331212111 - 211 = 12331331210063 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12331331212117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212609158801 + ... + 212609158858.
It is an arithmetic number, because the mean of its divisors is an integer number (3189137382450).
Almost surely, 212331331212111 is an apocalyptic number.
12331331212111 is a deficient number, since it is larger than the sum of its proper divisors (425218317689).
12331331212111 is an equidigital number, since it uses as much as digits as its factorization.
12331331212111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425218317688.
The product of its digits is 648, while the sum is 25.
Adding to 12331331212111 its reverse (11121213313321), we get a palindrome (23452544525432).
The spelling of 12331331212111 in words is "twelve trillion, three hundred thirty-one billion, three hundred thirty-one million, two hundred twelve thousand, one hundred eleven".
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