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123314343436607 = 532326685725219
BaseRepresentation
bin11100000010011101011011…
…101000101110000100111111
3121011121201212121200102011112
4130002131123220232010333
5112130340233404432412
61114133454411112235
734655111246442221
oct3402353350560477
9534551777612145
10123314343436607
1136323357087424
12119b719014267b
1353a6653592c6b
142264636020411
15e3ca508ca722
hex70275ba2e13f

123314343436607 has 4 divisors (see below), whose sum is σ = 125641029161880. Its totient is φ = 120987657711336.

The previous prime is 123314343436601. The next prime is 123314343436643. The reversal of 123314343436607 is 706634343413321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123314343436607 - 216 = 123314343371071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123314343436601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1163342862557 + ... + 1163342862662.

It is an arithmetic number, because the mean of its divisors is an integer number (31410257290470).

Almost surely, 2123314343436607 is an apocalyptic number.

123314343436607 is a deficient number, since it is larger than the sum of its proper divisors (2326685725273).

123314343436607 is an equidigital number, since it uses as much as digits as its factorization.

123314343436607 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2326685725272.

The product of its (nonzero) digits is 7838208, while the sum is 50.

Adding to 123314343436607 its reverse (706634343413321), we get a palindrome (829948686849928).

The spelling of 123314343436607 in words is "one hundred twenty-three trillion, three hundred fourteen billion, three hundred forty-three million, four hundred thirty-six thousand, six hundred seven".

Divisors: 1 53 2326685725219 123314343436607