Base | Representation |
---|---|
bin | 11100000010011101011111… |
… | …101000101101011111010111 |
3 | 121011121202001021221202220211 |
4 | 130002131133220231133113 |
5 | 112130340403044334223 |
6 | 1114133505205310251 |
7 | 34655113023024655 |
oct | 3402353750553727 |
9 | 534552037852824 |
10 | 123314410543063 |
11 | 36323390a51503 |
12 | 119b71aa705387 |
13 | 53a666445a71c |
14 | 2264640ccbdd5 |
15 | e3ca56733d0d |
hex | 70275fa2d7d7 |
123314410543063 has 2 divisors, whose sum is σ = 123314410543064. Its totient is φ = 123314410543062.
The previous prime is 123314410543057. The next prime is 123314410543067. The reversal of 123314410543063 is 360345014413321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123314410543063 - 217 = 123314410411991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123314410543067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657205271531 + 61657205271532.
It is an arithmetic number, because the mean of its divisors is an integer number (61657205271532).
Almost surely, 2123314410543063 is an apocalyptic number.
123314410543063 is a deficient number, since it is larger than the sum of its proper divisors (1).
123314410543063 is an equidigital number, since it uses as much as digits as its factorization.
123314410543063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 123314410543063 its reverse (360345014413321), we get a palindrome (483659424956384).
The spelling of 123314410543063 in words is "one hundred twenty-three trillion, three hundred fourteen billion, four hundred ten million, five hundred forty-three thousand, sixty-three".
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