Base | Representation |
---|---|
bin | 11100000010011101011111… |
… | …101000101111001011010010 |
3 | 121011121202001021222010101122 |
4 | 130002131133220233023102 |
5 | 112130340403100044340 |
6 | 1114133505205402242 |
7 | 34655113023054053 |
oct | 3402353750571322 |
9 | 534552037863348 |
10 | 123314410549970 |
11 | 36323390a56712 |
12 | 119b71aa709382 |
13 | 53a6664460903 |
14 | 2264640cd072a |
15 | e3ca56735db5 |
hex | 70275fa2f2d2 |
123314410549970 has 8 divisors (see below), whose sum is σ = 221965938989964. Its totient is φ = 49325764219984.
The previous prime is 123314410549969. The next prime is 123314410550039. The reversal of 123314410549970 is 79945014413321.
It can be written as a sum of positive squares in 2 ways, for example, as 121440422040001 + 1873988509969 = 11020001^2 + 1368937^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6165720527489 + ... + 6165720527508.
Almost surely, 2123314410549970 is an apocalyptic number.
123314410549970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
123314410549970 is a deficient number, since it is larger than the sum of its proper divisors (98651528439994).
123314410549970 is a wasteful number, since it uses less digits than its factorization.
123314410549970 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12331441055004.
The product of its (nonzero) digits is 3265920, while the sum is 53.
The spelling of 123314410549970 in words is "one hundred twenty-three trillion, three hundred fourteen billion, four hundred ten million, five hundred forty-nine thousand, nine hundred seventy".
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