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1233152513345 = 5246630502669
BaseRepresentation
bin10001111100011101100…
…111100001010101000001
311100212222112000021200002
4101330131213201111001
5130200444020411340
62342300310005345
7155043445262624
oct21743547412501
94325875007602
101233152513345
11435a8249a055
1217abb0346855
138c393b331cc
1443983519dbb
1522125482715
hex11f1d9e1541

1233152513345 has 4 divisors (see below), whose sum is σ = 1479783016020. Its totient is φ = 986522010672.

The previous prime is 1233152513339. The next prime is 1233152513407. The reversal of 1233152513345 is 5433152513321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 693349320976 + 539803192369 = 832676^2 + 734713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233152513345 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1233152513299 and 1233152513308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123315251330 + ... + 123315251339.

It is an arithmetic number, because the mean of its divisors is an integer number (369945754005).

Almost surely, 21233152513345 is an apocalyptic number.

It is an amenable number.

1233152513345 is a deficient number, since it is larger than the sum of its proper divisors (246630502675).

1233152513345 is an equidigital number, since it uses as much as digits as its factorization.

1233152513345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246630502674.

The product of its digits is 162000, while the sum is 38.

The spelling of 1233152513345 in words is "one trillion, two hundred thirty-three billion, one hundred fifty-two million, five hundred thirteen thousand, three hundred forty-five".

Divisors: 1 5 246630502669 1233152513345