Base | Representation |
---|---|
bin | 10001111100100000100… |
… | …100010110001101010101 |
3 | 11100220002222011010110010 |
4 | 101330200210112031111 |
5 | 130201044203404023 |
6 | 2342305234550433 |
7 | 155044616104545 |
oct | 21744044261525 |
9 | 4326088133403 |
10 | 1233202013013 |
11 | 435aa8428973 |
12 | 17b004a38419 |
13 | 8c3a1174959 |
14 | 43989d23325 |
15 | 221299ae093 |
hex | 11f20916355 |
1233202013013 has 4 divisors (see below), whose sum is σ = 1644269350688. Its totient is φ = 822134675340.
The previous prime is 1233202013009. The next prime is 1233202013047. The reversal of 1233202013013 is 3103102023321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1233202013013 - 22 = 1233202013009 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1233202012013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205533668833 + ... + 205533668838.
It is an arithmetic number, because the mean of its divisors is an integer number (411067337672).
Almost surely, 21233202013013 is an apocalyptic number.
It is an amenable number.
1233202013013 is a deficient number, since it is larger than the sum of its proper divisors (411067337675).
1233202013013 is an equidigital number, since it uses as much as digits as its factorization.
1233202013013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 411067337674.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1233202013013 its reverse (3103102023321), we get a palindrome (4336304036334).
The spelling of 1233202013013 in words is "one trillion, two hundred thirty-three billion, two hundred two million, thirteen thousand, thirteen".
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