Base | Representation |
---|---|
bin | 11100000010100100111000… |
… | …010011000100111101000101 |
3 | 121011122111111221120002011211 |
4 | 130002210320103010331011 |
5 | 112131003123131321143 |
6 | 1114141300123531421 |
7 | 34655513363351611 |
oct | 3402447023047505 |
9 | 534574457502154 |
10 | 123322340495173 |
11 | 36326790225936 |
12 | 119b8842389b71 |
13 | 53a7329316291 |
14 | 2264b94160341 |
15 | e3cd6c9e449d |
hex | 7029384c4f45 |
123322340495173 has 2 divisors, whose sum is σ = 123322340495174. Its totient is φ = 123322340495172.
The previous prime is 123322340495147. The next prime is 123322340495209. The reversal of 123322340495173 is 371594043223321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65548082015329 + 57774258479844 = 8096177^2 + 7600938^2 .
It is an emirp because it is prime and its reverse (371594043223321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123322340495173 - 225 = 123322306940741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123322340595173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61661170247586 + 61661170247587.
It is an arithmetic number, because the mean of its divisors is an integer number (61661170247587).
Almost surely, 2123322340495173 is an apocalyptic number.
It is an amenable number.
123322340495173 is a deficient number, since it is larger than the sum of its proper divisors (1).
123322340495173 is an equidigital number, since it uses as much as digits as its factorization.
123322340495173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3265920, while the sum is 49.
The spelling of 123322340495173 in words is "one hundred twenty-three trillion, three hundred twenty-two billion, three hundred forty million, four hundred ninety-five thousand, one hundred seventy-three".
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