Search a number
-
+
123322340495173 is a prime number
BaseRepresentation
bin11100000010100100111000…
…010011000100111101000101
3121011122111111221120002011211
4130002210320103010331011
5112131003123131321143
61114141300123531421
734655513363351611
oct3402447023047505
9534574457502154
10123322340495173
1136326790225936
12119b8842389b71
1353a7329316291
142264b94160341
15e3cd6c9e449d
hex7029384c4f45

123322340495173 has 2 divisors, whose sum is σ = 123322340495174. Its totient is φ = 123322340495172.

The previous prime is 123322340495147. The next prime is 123322340495209. The reversal of 123322340495173 is 371594043223321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65548082015329 + 57774258479844 = 8096177^2 + 7600938^2 .

It is an emirp because it is prime and its reverse (371594043223321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123322340495173 - 225 = 123322306940741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123322340595173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61661170247586 + 61661170247587.

It is an arithmetic number, because the mean of its divisors is an integer number (61661170247587).

Almost surely, 2123322340495173 is an apocalyptic number.

It is an amenable number.

123322340495173 is a deficient number, since it is larger than the sum of its proper divisors (1).

123322340495173 is an equidigital number, since it uses as much as digits as its factorization.

123322340495173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 49.

The spelling of 123322340495173 in words is "one hundred twenty-three trillion, three hundred twenty-two billion, three hundred forty million, four hundred ninety-five thousand, one hundred seventy-three".