Base | Representation |
---|---|
bin | 11100000010100101100110… |
… | …110101101110110001101011 |
3 | 121011122120112100211122222122 |
4 | 130002211212311232301223 |
5 | 112131011223030100212 |
6 | 1114141505415541455 |
7 | 34655541624351032 |
oct | 3402454665566153 |
9 | 534576470748878 |
10 | 123323121331307 |
11 | 36327050a67657 |
12 | 119b8a1b98a88b |
13 | 53a74220194b1 |
14 | 2264c29b3b719 |
15 | e3cdb6333272 |
hex | 702966d6ec6b |
123323121331307 has 2 divisors, whose sum is σ = 123323121331308. Its totient is φ = 123323121331306.
The previous prime is 123323121331279. The next prime is 123323121331411. The reversal of 123323121331307 is 703133121323321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123323121331307 is a prime.
It is not a weakly prime, because it can be changed into another prime (123323121331607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61661560665653 + 61661560665654.
It is an arithmetic number, because the mean of its divisors is an integer number (61661560665654).
Almost surely, 2123323121331307 is an apocalyptic number.
123323121331307 is a deficient number, since it is larger than the sum of its proper divisors (1).
123323121331307 is an equidigital number, since it uses as much as digits as its factorization.
123323121331307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 35.
Adding to 123323121331307 its reverse (703133121323321), we get a palindrome (826456242654628).
The spelling of 123323121331307 in words is "one hundred twenty-three trillion, three hundred twenty-three billion, one hundred twenty-one million, three hundred thirty-one thousand, three hundred seven".
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