Base | Representation |
---|---|
bin | 11100000010100101100110… |
… | …110101101110110011010011 |
3 | 121011122120112100211200010111 |
4 | 130002211212311232303103 |
5 | 112131011223030101121 |
6 | 1114141505415542151 |
7 | 34655541624351241 |
oct | 3402454665566323 |
9 | 534576470750114 |
10 | 123323121331411 |
11 | 36327050a67741 |
12 | 119b8a1b98a957 |
13 | 53a7422019561 |
14 | 2264c29b3b791 |
15 | e3cdb63332e1 |
hex | 702966d6ecd3 |
123323121331411 has 2 divisors, whose sum is σ = 123323121331412. Its totient is φ = 123323121331410.
The previous prime is 123323121331307. The next prime is 123323121331433. The reversal of 123323121331411 is 114133121323321.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (114133121323321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123323121331411 - 217 = 123323121200339 is a prime.
It is not a weakly prime, because it can be changed into another prime (123323121331811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61661560665705 + 61661560665706.
It is an arithmetic number, because the mean of its divisors is an integer number (61661560665706).
Almost surely, 2123323121331411 is an apocalyptic number.
123323121331411 is a deficient number, since it is larger than the sum of its proper divisors (1).
123323121331411 is an equidigital number, since it uses as much as digits as its factorization.
123323121331411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7776, while the sum is 31.
Adding to 123323121331411 its reverse (114133121323321), we get a palindrome (237456242654732).
The spelling of 123323121331411 in words is "one hundred twenty-three trillion, three hundred twenty-three billion, one hundred twenty-one million, three hundred thirty-one thousand, four hundred eleven".
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