Base | Representation |
---|---|
bin | 10110111110001001… |
… | …10100000100111010 |
3 | 1011211110210201001121 |
4 | 23133010310010322 |
5 | 200224111000032 |
6 | 5355424335454 |
7 | 614416440046 |
oct | 133704640472 |
9 | 34743721047 |
10 | 12332515642 |
11 | 5259424597 |
12 | 248217458a |
13 | 1217008645 |
14 | 84dc57026 |
15 | 4c2a53a97 |
hex | 2df13413a |
12332515642 has 4 divisors (see below), whose sum is σ = 18498773466. Its totient is φ = 6166257820.
The previous prime is 12332515619. The next prime is 12332515661. The reversal of 12332515642 is 24651523321.
12332515642 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8208178801 + 4124336841 = 90599^2 + 64221^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12332515598 and 12332515607.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3083128909 + ... + 3083128912.
Almost surely, 212332515642 is an apocalyptic number.
12332515642 is a deficient number, since it is larger than the sum of its proper divisors (6166257824).
12332515642 is an equidigital number, since it uses as much as digits as its factorization.
12332515642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6166257823.
The product of its digits is 43200, while the sum is 34.
The spelling of 12332515642 in words is "twelve billion, three hundred thirty-two million, five hundred fifteen thousand, six hundred forty-two".
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