Base | Representation |
---|---|
bin | 11100000010101101001010… |
… | …110101000111011001001110 |
3 | 121011200100111021001222100111 |
4 | 130002231022311013121032 |
5 | 112131124340240430132 |
6 | 1114145331243550234 |
7 | 34656250063330132 |
oct | 3402551265073116 |
9 | 534610437058314 |
10 | 123331241342542 |
11 | 3632a538554242 |
12 | 119ba50722b37a |
13 | 53a811738b67c |
14 | 226539a3253c2 |
15 | e3d1de137647 |
hex | 702b4ad4764e |
123331241342542 has 16 divisors (see below), whose sum is σ = 190967144873472. Its totient is φ = 59675581429560.
The previous prime is 123331241342539. The next prime is 123331241342611. The reversal of 123331241342542 is 245243142133321.
It is a junction number, because it is equal to n+sod(n) for n = 123331241342495 and 123331241342504.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9232008 + ... + 18217915.
It is an arithmetic number, because the mean of its divisors is an integer number (11935446554592).
Almost surely, 2123331241342542 is an apocalyptic number.
123331241342542 is a deficient number, since it is larger than the sum of its proper divisors (67635903530930).
123331241342542 is a wasteful number, since it uses less digits than its factorization.
123331241342542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27522423.
The product of its digits is 414720, while the sum is 40.
Adding to 123331241342542 its reverse (245243142133321), we get a palindrome (368574383475863).
The spelling of 123331241342542 in words is "one hundred twenty-three trillion, three hundred thirty-one billion, two hundred forty-one million, three hundred forty-two thousand, five hundred forty-two".
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