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12333125410493 is a prime number
BaseRepresentation
bin1011001101111000011110…
…0011110001111010111101
31121200000221201022100002212
42303132013203301322331
53104031220101113433
642121432023430205
72412016226203556
oct263360743617275
947600851270085
1012333125410493
113a254a3852308
1214722aa8b5365
136b60162675b4
14308cd829932d
15165c2d7c0d48
hexb37878f1ebd

12333125410493 has 2 divisors, whose sum is σ = 12333125410494. Its totient is φ = 12333125410492.

The previous prime is 12333125410429. The next prime is 12333125410537. The reversal of 12333125410493 is 39401452133321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11797012963684 + 536112446809 = 3434678^2 + 732197^2 .

It is a cyclic number.

It is not a de Polignac number, because 12333125410493 - 26 = 12333125410429 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12333125410493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12333125410393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166562705246 + 6166562705247.

It is an arithmetic number, because the mean of its divisors is an integer number (6166562705247).

Almost surely, 212333125410493 is an apocalyptic number.

It is an amenable number.

12333125410493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12333125410493 is an equidigital number, since it uses as much as digits as its factorization.

12333125410493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 12333125410493 in words is "twelve trillion, three hundred thirty-three billion, one hundred twenty-five million, four hundred ten thousand, four hundred ninety-three".