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1233400140073 is a prime number
BaseRepresentation
bin10001111100101100011…
…000001001000100101001
311100220121202222000200101
4101330230120021010221
5130202000413440243
62342341033305401
7155052543131503
oct21745430110451
94326552860611
101233400140073
1143609a251742
1217b05b265261
138c4032245ba
14439a8378d73
152213c09854d
hex11f2c609129

1233400140073 has 2 divisors, whose sum is σ = 1233400140074. Its totient is φ = 1233400140072.

The previous prime is 1233400140029. The next prime is 1233400140107. The reversal of 1233400140073 is 3700410043321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1231152242329 + 2247897744 = 1109573^2 + 47412^2 .

It is an emirp because it is prime and its reverse (3700410043321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233400140073 is a prime.

It is not a weakly prime, because it can be changed into another prime (1233400140013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616700070036 + 616700070037.

It is an arithmetic number, because the mean of its divisors is an integer number (616700070037).

Almost surely, 21233400140073 is an apocalyptic number.

It is an amenable number.

1233400140073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233400140073 is an equidigital number, since it uses as much as digits as its factorization.

1233400140073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 1233400140073 its reverse (3700410043321), we get a palindrome (4933810183394).

The spelling of 1233400140073 in words is "one trillion, two hundred thirty-three billion, four hundred million, one hundred forty thousand, seventy-three".