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12334301143 = 50032465381
BaseRepresentation
bin10110111110010111…
…00111111111010111
31011211121011102022021
423133023213333113
5200230040114033
65355530514011
7614440554433
oct133713477727
934747142267
1012334301143
11525a43400a
122482895907
1312174b2258
1485019d9c3
154c2ca7b2d
hex2df2e7fd7

12334301143 has 4 divisors (see below), whose sum is σ = 12336771528. Its totient is φ = 12331830760.

The previous prime is 12334301131. The next prime is 12334301153. The reversal of 12334301143 is 34110343321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12334301143 - 29 = 12334300631 is a prime.

It is a super-2 number, since 2×123343011432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12334301123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1227688 + ... + 1237693.

It is an arithmetic number, because the mean of its divisors is an integer number (3084192882).

Almost surely, 212334301143 is an apocalyptic number.

12334301143 is a deficient number, since it is larger than the sum of its proper divisors (2470385).

12334301143 is an equidigital number, since it uses as much as digits as its factorization.

12334301143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2470384.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12334301143 its reverse (34110343321), we get a palindrome (46444644464).

The spelling of 12334301143 in words is "twelve billion, three hundred thirty-four million, three hundred one thousand, one hundred forty-three".

Divisors: 1 5003 2465381 12334301143