Base | Representation |
---|---|
bin | 11100000010111010010110… |
… | …110010000010011010100111 |
3 | 121011201201001001001000011202 |
4 | 130002322112302002122213 |
5 | 112131342340012143043 |
6 | 1114200032243553115 |
7 | 34660261003252133 |
oct | 3402722662023247 |
9 | 534651031030152 |
10 | 123345400506023 |
11 | 36335543a83343 |
12 | 11a011b908b79b |
13 | 53a9562957307 |
14 | 2265d409d03c3 |
15 | e3d76c20a1b8 |
hex | 702e96c826a7 |
123345400506023 has 2 divisors, whose sum is σ = 123345400506024. Its totient is φ = 123345400506022.
The previous prime is 123345400506019. The next prime is 123345400506073. The reversal of 123345400506023 is 320605004543321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123345400506023 - 22 = 123345400506019 is a prime.
It is a super-3 number, since 3×1233454005060233 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123345400506073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61672700253011 + 61672700253012.
It is an arithmetic number, because the mean of its divisors is an integer number (61672700253012).
Almost surely, 2123345400506023 is an apocalyptic number.
123345400506023 is a deficient number, since it is larger than the sum of its proper divisors (1).
123345400506023 is an equidigital number, since it uses as much as digits as its factorization.
123345400506023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
The spelling of 123345400506023 in words is "one hundred twenty-three trillion, three hundred forty-five billion, four hundred million, five hundred six thousand, twenty-three".
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