123345401013301 has 4 divisors (see below), whose sum is σ = 123347191785004. Its totient is φ = 123343610241600.

The previous prime is 123345401013299. The next prime is 123345401013311. The reversal of 123345401013301 is 103310104543321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12122750187076 + 111222650826225 = 3481774^2 + 10546215^2 .

It is a cyclic number.

It is not a de Polignac number, because 123345401013301 - 2¹ = 123345401013299 is a prime.

It is a super-3 number, since 3×123345401013301³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123345401013311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 895282530 + ... + 895420291.

It is an arithmetic number, because the mean of its divisors is an integer number (30836797946251).

Almost surely, 2^{123345401013301} is an apocalyptic number.

It is an amenable number.

123345401013301 is a deficient number, since it is larger than the sum of its proper divisors (1790771703).

123345401013301 is an equidigital number, since it uses as much as digits as its factorization.

123345401013301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1790771702.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 123345401013301 its reverse (103310104543321), we get a palindrome (226655505556622).

The spelling of 123345401013301 in words is "one hundred twenty-three trillion, three hundred forty-five billion, four hundred one million, thirteen thousand, three hundred one".