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123351519113 is a prime number
BaseRepresentation
bin111001011100001010…
…0101100111110001001
3102210101120122102101222
41302320110230332021
54010110442102423
6132400015051425
711624523420104
oct1627024547611
9383346572358
10123351519113
1148349798029
121baa6210b75
13b82a667384
145d824d373b
15331e3333c8
hex1cb852cf89

123351519113 has 2 divisors, whose sum is σ = 123351519114. Its totient is φ = 123351519112.

The previous prime is 123351519107. The next prime is 123351519127. The reversal of 123351519113 is 311915153321.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63848698489 + 59502820624 = 252683^2 + 243932^2 .

It is an emirp because it is prime and its reverse (311915153321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123351519113 - 210 = 123351518089 is a prime.

It is not a weakly prime, because it can be changed into another prime (123351569113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61675759556 + 61675759557.

It is an arithmetic number, because the mean of its divisors is an integer number (61675759557).

Almost surely, 2123351519113 is an apocalyptic number.

It is an amenable number.

123351519113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123351519113 is an equidigital number, since it uses as much as digits as its factorization.

123351519113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12150, while the sum is 35.

The spelling of 123351519113 in words is "one hundred twenty-three billion, three hundred fifty-one million, five hundred nineteen thousand, one hundred thirteen".