Base | Representation |
---|---|
bin | 11100000011000010100100… |
… | …110010011110001110010111 |
3 | 121011202112211001200212122020 |
4 | 130003002210302132032113 |
5 | 112132013423202414133 |
6 | 1114204052052504223 |
7 | 34661022462025464 |
oct | 3403024462361627 |
9 | 534675731625566 |
10 | 123354225435543 |
11 | 36339262469523 |
12 | 11a02a6061b073 |
13 | 53aa33b06b3bb |
14 | 226653aa7266b |
15 | e3dad6d540b3 |
hex | 7030a4c9e397 |
123354225435543 has 4 divisors (see below), whose sum is σ = 164472300580728. Its totient is φ = 82236150290360.
The previous prime is 123354225435533. The next prime is 123354225435587. The reversal of 123354225435543 is 345534522453321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123354225435543 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123354225435503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20559037572588 + ... + 20559037572593.
It is an arithmetic number, because the mean of its divisors is an integer number (41118075145182).
Almost surely, 2123354225435543 is an apocalyptic number.
123354225435543 is a deficient number, since it is larger than the sum of its proper divisors (41118075145185).
123354225435543 is an equidigital number, since it uses as much as digits as its factorization.
123354225435543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41118075145184.
The product of its digits is 25920000, while the sum is 51.
Adding to 123354225435543 its reverse (345534522453321), we get a palindrome (468888747888864).
The spelling of 123354225435543 in words is "one hundred twenty-three trillion, three hundred fifty-four billion, two hundred twenty-five million, four hundred thirty-five thousand, five hundred forty-three".
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