1234012433 has 2 divisors, whose sum is σ = 1234012434. Its totient is φ = 1234012432.

The previous prime is 1234012421. The next prime is 1234012453. The reversal of 1234012433 is 3342104321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1228362304 + 5650129 = 35048^2 + 2377^2 .

It is a cyclic number.

It is not a de Polignac number, because 1234012433 - 2¹² = 1234008337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1234012399 and 1234012408.

It is not a weakly prime, because it can be changed into another prime (1234012453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617006216 + 617006217.

It is an arithmetic number, because the mean of its divisors is an integer number (617006217).

Almost surely, 2^1234012433 is an apocalyptic number.

It is an amenable number.

1234012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1234012433 is an equidigital number, since it uses as much as digits as its factorization.

1234012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1234012433 is about 35128.5131054532. The cubic root of 1234012433 is about 1072.6050691543.

Adding to 1234012433 its reverse (3342104321), we get a palindrome (4576116754).

The spelling of 1234012433 in words is "one billion, two hundred thirty-four million, twelve thousand, four hundred thirty-three".