Base | Representation |
---|---|
bin | 1011001110010011010010… |
… | …1110000101011101111111 |
3 | 1121200201112111121200202112 |
4 | 2303210310232011131333 |
5 | 3104140441314201123 |
6 | 42125022311244235 |
7 | 2412362525240144 |
oct | 263446456053577 |
9 | 47621474550675 |
10 | 12340325537663 |
11 | 3a28559066432 |
12 | 147377a07967b |
13 | 6b68c2b70686 |
14 | 3093bc62c3cb |
15 | 16600096bd78 |
hex | b3934b8577f |
12340325537663 has 4 divisors (see below), whose sum is σ = 12340688554440. Its totient is φ = 12339962520888.
The previous prime is 12340325537623. The next prime is 12340325537707. The reversal of 12340325537663 is 36673552304321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12340325537663 - 210 = 12340325536639 is a prime.
It is a super-2 number, since 2×123403255376632 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12340325537623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181457393 + ... + 181525386.
It is an arithmetic number, because the mean of its divisors is an integer number (3085172138610).
Almost surely, 212340325537663 is an apocalyptic number.
12340325537663 is a deficient number, since it is larger than the sum of its proper divisors (363016777).
12340325537663 is an equidigital number, since it uses as much as digits as its factorization.
12340325537663 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 363016776.
The product of its (nonzero) digits is 8164800, while the sum is 50.
The spelling of 12340325537663 in words is "twelve trillion, three hundred forty billion, three hundred twenty-five million, five hundred thirty-seven thousand, six hundred sixty-three".
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