Base | Representation |
---|---|
bin | 10001111101010110111… |
… | …000011000010001100011 |
3 | 11100222110110202221200021 |
4 | 101331112320120101203 |
5 | 130204430441442034 |
6 | 2342535505334311 |
7 | 155106322256551 |
oct | 21752670302143 |
9 | 4328413687607 |
10 | 1234113234019 |
11 | 436425824786 |
12 | 17b21a037397 |
13 | 8c4b7b99893 |
14 | 43a34d60bd1 |
15 | 2217e9a56b4 |
hex | 11f56e18463 |
1234113234019 has 2 divisors, whose sum is σ = 1234113234020. Its totient is φ = 1234113234018.
The previous prime is 1234113234017. The next prime is 1234113234089. The reversal of 1234113234019 is 9104323114321.
It is a weak prime.
It is an emirp because it is prime and its reverse (9104323114321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1234113234019 - 21 = 1234113234017 is a prime.
It is a super-2 number, since 2×12341132340192 (a number of 25 digits) contains 22 as substring.
Together with 1234113234017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1234113234017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617056617009 + 617056617010.
It is an arithmetic number, because the mean of its divisors is an integer number (617056617010).
Almost surely, 21234113234019 is an apocalyptic number.
1234113234019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234113234019 is an equidigital number, since it uses as much as digits as its factorization.
1234113234019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 1234113234019 in words is "one trillion, two hundred thirty-four billion, one hundred thirteen million, two hundred thirty-four thousand, nineteen".
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