Base | Representation |
---|---|
bin | 10001111101011000000… |
… | …100010100101000011001 |
3 | 11100222111212020101100102 |
4 | 101331120010110220121 |
5 | 130210001041021131 |
6 | 2342541500145145 |
7 | 155106653423462 |
oct | 21753004245031 |
9 | 4328455211312 |
10 | 1234133142041 |
11 | 436435a91998 |
12 | 17b2248381b5 |
13 | 8c4bc04a187 |
14 | 43a37863d69 |
15 | 221815d91cb |
hex | 11f58114a19 |
1234133142041 has 4 divisors (see below), whose sum is σ = 1234135434084. Its totient is φ = 1234130850000.
The previous prime is 1234133142037. The next prime is 1234133142059. The reversal of 1234133142041 is 1402413314321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 73859476441 + 1160273665600 = 271771^2 + 1077160^2 .
It is a cyclic number.
It is not a de Polignac number, because 1234133142041 - 22 = 1234133142037 is a prime.
It is a super-2 number, since 2×12341331420412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1234133141995 and 1234133142013.
It is not an unprimeable number, because it can be changed into a prime (1234133142241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150791 + ... + 1578291.
It is an arithmetic number, because the mean of its divisors is an integer number (308533858521).
Almost surely, 21234133142041 is an apocalyptic number.
It is an amenable number.
1234133142041 is a deficient number, since it is larger than the sum of its proper divisors (2292043).
1234133142041 is an equidigital number, since it uses as much as digits as its factorization.
1234133142041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2292042.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1234133142041 its reverse (1402413314321), we get a palindrome (2636546456362).
The spelling of 1234133142041 in words is "one trillion, two hundred thirty-four billion, one hundred thirty-three million, one hundred forty-two thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •