Base | Representation |
---|---|
bin | 11100000100000000111100… |
… | …110100001111000110010001 |
3 | 121011222221200200011220121002 |
4 | 130010000330310033012101 |
5 | 112134113104314403040 |
6 | 1114254530005511345 |
7 | 34665613256042000 |
oct | 3404007464170621 |
9 | 534887620156532 |
10 | 123421200544145 |
11 | 36364701139949 |
12 | 11a13a32412555 |
13 | 53b37528c788a |
14 | 2269891a42c37 |
15 | e40706b05a15 |
hex | 70403cd0f191 |
123421200544145 has 64 divisors (see below), whose sum is σ = 174260764800000. Its totient is φ = 83875711546368.
The previous prime is 123421200544121. The next prime is 123421200544207. The reversal of 123421200544145 is 541445002124321.
It is a de Polignac number, because none of the positive numbers 2k-123421200544145 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123421200544099 and 123421200544108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3511354031 + ... + 3511389179.
It is an arithmetic number, because the mean of its divisors is an integer number (2722824450000).
Almost surely, 2123421200544145 is an apocalyptic number.
It is an amenable number.
123421200544145 is a deficient number, since it is larger than the sum of its proper divisors (50839564255855).
123421200544145 is a wasteful number, since it uses less digits than its factorization.
123421200544145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53407 (or 53393 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 123421200544145 its reverse (541445002124321), we get a palindrome (664866202668466).
The spelling of 123421200544145 in words is "one hundred twenty-three trillion, four hundred twenty-one billion, two hundred million, five hundred forty-four thousand, one hundred forty-five".
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