12342202344433 has 4 divisors (see below), whose sum is σ = 13291602524788. Its totient is φ = 11392802164080.

The previous prime is 12342202344347. The next prime is 12342202344509. The reversal of 12342202344433 is 33444320224321.

12342202344433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 658610156304 + 11683592188129 = 811548^2 + 3418127^2 .

It is a cyclic number.

It is not a de Polignac number, because 12342202344433 - 2³⁷ = 12204763390961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12342202344392 and 12342202344401.

It is not an unprimeable number, because it can be changed into a prime (12342202344233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474700090158 + ... + 474700090183.

It is an arithmetic number, because the mean of its divisors is an integer number (3322900631197).

Almost surely, 2^{12342202344433} is an apocalyptic number.

12342202344433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12342202344433 is a deficient number, since it is larger than the sum of its proper divisors (949400180355).

12342202344433 is an equidigital number, since it uses as much as digits as its factorization.

12342202344433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 949400180354.

The product of its (nonzero) digits is 331776, while the sum is 37.

Adding to 12342202344433 its reverse (33444320224321), we get a palindrome (45786522568754).

The spelling of 12342202344433 in words is "twelve trillion, three hundred forty-two billion, two hundred two million, three hundred forty-four thousand, four hundred thirty-three".