Search a number
-
+
1234343211133 is a prime number
BaseRepresentation
bin10001111101100100100…
…101101011000001111101
311101000001111111222222011
4101331210211223001331
5130210413330224013
62343014402451221
7155115114116014
oct21754445530175
94330044458864
101234343211133
11436533621a0a
1217b283063b11
138c52371b606
1443a57707a7b
1522194c81c3d
hex11f6496b07d

1234343211133 has 2 divisors, whose sum is σ = 1234343211134. Its totient is φ = 1234343211132.

The previous prime is 1234343211119. The next prime is 1234343211161. The reversal of 1234343211133 is 3311123434321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 956274719449 + 278068491684 = 977893^2 + 527322^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1234343211133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1234343211095 and 1234343211104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1234343211533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617171605566 + 617171605567.

It is an arithmetic number, because the mean of its divisors is an integer number (617171605567).

Almost surely, 21234343211133 is an apocalyptic number.

It is an amenable number.

1234343211133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1234343211133 is an equidigital number, since it uses as much as digits as its factorization.

1234343211133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 31.

Adding to 1234343211133 its reverse (3311123434321), we get a palindrome (4545466645454).

The spelling of 1234343211133 in words is "one trillion, two hundred thirty-four billion, three hundred forty-three million, two hundred eleven thousand, one hundred thirty-three".