Base | Representation |
---|---|
bin | 11100000100010101101010… |
… | …000000000000101100111111 |
3 | 121012002002002010022011000111 |
4 | 130010111222000000230333 |
5 | 112134444122430121421 |
6 | 1114313044102010451 |
7 | 35000331233413336 |
oct | 3404255200005477 |
9 | 535062063264014 |
10 | 123443433442111 |
11 | 36373080018192 |
12 | 11a181b8116a27 |
13 | 53b5886a81bc3 |
14 | 226a9a06cad1d |
15 | e410a88daee1 |
hex | 70456a000b3f |
123443433442111 has 2 divisors, whose sum is σ = 123443433442112. Its totient is φ = 123443433442110.
The previous prime is 123443433442031. The next prime is 123443433442183. The reversal of 123443433442111 is 111244334344321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123443433442111 - 29 = 123443433441599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123443433442411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61721716721055 + 61721716721056.
It is an arithmetic number, because the mean of its divisors is an integer number (61721716721056).
Almost surely, 2123443433442111 is an apocalyptic number.
123443433442111 is a deficient number, since it is larger than the sum of its proper divisors (1).
123443433442111 is an equidigital number, since it uses as much as digits as its factorization.
123443433442111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 331776, while the sum is 40.
Adding to 123443433442111 its reverse (111244334344321), we get a palindrome (234687767786432).
The spelling of 123443433442111 in words is "one hundred twenty-three trillion, four hundred forty-three billion, four hundred thirty-three million, four hundred forty-two thousand, one hundred eleven".
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