12350414113 has 8 divisors (see below), whose sum is σ = 12541554432. Its totient is φ = 12159474096.

The previous prime is 12350414107. The next prime is 12350414123. The reversal of 12350414113 is 31141405321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12350414113 - 2⁹ = 12350413601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12350414123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76656 + ... + 174862.

It is an arithmetic number, because the mean of its divisors is an integer number (1567694304).

Almost surely, 2^12350414113 is an apocalyptic number.

It is an amenable number.

12350414113 is a deficient number, since it is larger than the sum of its proper divisors (191140319).

12350414113 is an equidigital number, since it uses as much as digits as its factorization.

12350414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100151.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12350414113 its reverse (31141405321), we get a palindrome (43491819434).

The spelling of 12350414113 in words is "twelve billion, three hundred fifty million, four hundred fourteen thousand, one hundred thirteen".