Base | Representation |
---|---|
bin | 10001111110001110111… |
… | …010101001110101100111 |
3 | 11101001212222210000022112 |
4 | 101332032322221311213 |
5 | 130213342124314333 |
6 | 2343213051351235 |
7 | 155141526204254 |
oct | 21761672516547 |
9 | 4331788700275 |
10 | 1235053354343 |
11 | 43686846a026 |
12 | 17b440a5251b |
13 | 8c60789c7b3 |
14 | 43ac3b6242b |
15 | 221d72a9948 |
hex | 11f8eea9d67 |
1235053354343 has 2 divisors, whose sum is σ = 1235053354344. Its totient is φ = 1235053354342.
The previous prime is 1235053354303. The next prime is 1235053354349. The reversal of 1235053354343 is 3434533505321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1235053354343 - 212 = 1235053350247 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1235053354343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1235053354349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617526677171 + 617526677172.
It is an arithmetic number, because the mean of its divisors is an integer number (617526677172).
Almost surely, 21235053354343 is an apocalyptic number.
1235053354343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1235053354343 is an equidigital number, since it uses as much as digits as its factorization.
1235053354343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 1235053354343 its reverse (3434533505321), we get a palindrome (4669586859664).
The spelling of 1235053354343 in words is "one trillion, two hundred thirty-five billion, fifty-three million, three hundred fifty-four thousand, three hundred forty-three".
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