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1235053354343 is a prime number
BaseRepresentation
bin10001111110001110111…
…010101001110101100111
311101001212222210000022112
4101332032322221311213
5130213342124314333
62343213051351235
7155141526204254
oct21761672516547
94331788700275
101235053354343
1143686846a026
1217b440a5251b
138c60789c7b3
1443ac3b6242b
15221d72a9948
hex11f8eea9d67

1235053354343 has 2 divisors, whose sum is σ = 1235053354344. Its totient is φ = 1235053354342.

The previous prime is 1235053354303. The next prime is 1235053354349. The reversal of 1235053354343 is 3434533505321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1235053354343 - 212 = 1235053350247 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1235053354343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1235053354349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617526677171 + 617526677172.

It is an arithmetic number, because the mean of its divisors is an integer number (617526677172).

Almost surely, 21235053354343 is an apocalyptic number.

1235053354343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1235053354343 is an equidigital number, since it uses as much as digits as its factorization.

1235053354343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 41.

Adding to 1235053354343 its reverse (3434533505321), we get a palindrome (4669586859664).

The spelling of 1235053354343 in words is "one trillion, two hundred thirty-five billion, fifty-three million, three hundred fifty-four thousand, three hundred forty-three".