123512020341401 has 8 divisors (see below), whose sum is σ = 123787578436200. Its totient is φ = 123236464361472.

The previous prime is 123512020341383. The next prime is 123512020341439. The reversal of 123512020341401 is 104143020215321.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 91273642268176 + 32238378073225 = 9553724^2 + 5677885^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 123512020341401 - 2¹⁴ = 123512020325017 is a prime.

It is a super-3 number, since 3×123512020341401³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123512020341461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 207820601 + ... + 208414073.

It is an arithmetic number, because the mean of its divisors is an integer number (15473447304525).

Almost surely, 2^{123512020341401} is an apocalyptic number.

It is an amenable number.

123512020341401 is a deficient number, since it is larger than the sum of its proper divisors (275558094799).

123512020341401 is an equidigital number, since it uses as much as digits as its factorization.

123512020341401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1057435.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 123512020341401 its reverse (104143020215321), we get a palindrome (227655040556722).

The spelling of 123512020341401 in words is "one hundred twenty-three trillion, five hundred twelve billion, twenty million, three hundred forty-one thousand, four hundred one".