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123524343987857 is a prime number
BaseRepresentation
bin11100000101100001000000…
…101001001111111010010001
3121012100210220220202201221222
4130011201000221033322101
5112142310324030102412
61114414144503454425
735006224252615301
oct3405410051177221
9535323826681858
10123524343987857
11363a441a9a980a
1211a2ba18a57415
1353c03ac733487
142270878369601
15e43241cbb072
hex705840a4fe91

123524343987857 has 2 divisors, whose sum is σ = 123524343987858. Its totient is φ = 123524343987856.

The previous prime is 123524343987853. The next prime is 123524343987859. The reversal of 123524343987857 is 758789343425321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66747576466561 + 56776767521296 = 8169919^2 + 7535036^2 .

It is a cyclic number.

It is not a de Polignac number, because 123524343987857 - 22 = 123524343987853 is a prime.

Together with 123524343987859, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (123524343987853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61762171993928 + 61762171993929.

It is an arithmetic number, because the mean of its divisors is an integer number (61762171993929).

Almost surely, 2123524343987857 is an apocalyptic number.

It is an amenable number.

123524343987857 is a deficient number, since it is larger than the sum of its proper divisors (1).

123524343987857 is an equidigital number, since it uses as much as digits as its factorization.

123524343987857 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1219276800, while the sum is 71.

The spelling of 123524343987857 in words is "one hundred twenty-three trillion, five hundred twenty-four billion, three hundred forty-three million, nine hundred eighty-seven thousand, eight hundred fifty-seven".