Base | Representation |
---|---|
bin | 1011001111000000110110… |
… | …0011101100101001101011 |
3 | 1121201220002200111201101021 |
4 | 2303300031203230221223 |
5 | 3104341012132430120 |
6 | 42134403521033311 |
7 | 2413304534345224 |
oct | 263601543545153 |
9 | 47656080451337 |
10 | 12352553405035 |
11 | 3a32763404148 |
12 | 1476011185837 |
13 | 6b7ac129885c |
14 | 309c1c60424b |
15 | 1664b91edaaa |
hex | b3c0d8eca6b |
12352553405035 has 16 divisors (see below), whose sum is σ = 15334341935040. Its totient is φ = 9541196945280.
The previous prime is 12352553404999. The next prime is 12352553405051. The reversal of 12352553405035 is 53050435525321.
It is a de Polignac number, because none of the positive numbers 2k-12352553405035 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12352553404982 and 12352553405000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19299409 + ... + 19929181.
It is an arithmetic number, because the mean of its divisors is an integer number (958396370940).
Almost surely, 212352553405035 is an apocalyptic number.
12352553405035 is a deficient number, since it is larger than the sum of its proper divisors (2981788530005).
12352553405035 is a wasteful number, since it uses less digits than its factorization.
12352553405035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 765078.
The product of its (nonzero) digits is 1350000, while the sum is 43.
The spelling of 12352553405035 in words is "twelve trillion, three hundred fifty-two billion, five hundred fifty-three million, four hundred five thousand, thirty-five".
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