Base | Representation |
---|---|
bin | 10111000000100110… |
… | …00110111100011001 |
3 | 1011212220102110101200 |
4 | 23200103012330121 |
5 | 200244334241103 |
6 | 5401440304413 |
7 | 615056052216 |
oct | 134023067431 |
9 | 34786373350 |
10 | 12353040153 |
11 | 5269a729a3 |
12 | 2489012109 |
13 | 121b34371c |
14 | 85287ab0d |
15 | 4c475a0a3 |
hex | 2e04c6f19 |
12353040153 has 24 divisors (see below), whose sum is σ = 17927800800. Its totient is φ = 8196439680.
The previous prime is 12353040143. The next prime is 12353040179. The reversal of 12353040153 is 35104035321.
12353040153 is a `hidden beast` number, since 123 + 530 + 4 + 0 + 1 + 5 + 3 = 666.
It is not a de Polignac number, because 12353040153 - 25 = 12353040121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12353040103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1912273 + ... + 1918721.
It is an arithmetic number, because the mean of its divisors is an integer number (746991700).
Almost surely, 212353040153 is an apocalyptic number.
It is an amenable number.
12353040153 is a deficient number, since it is larger than the sum of its proper divisors (5574760647).
12353040153 is a wasteful number, since it uses less digits than its factorization.
12353040153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7429 (or 7426 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 12353040153 its reverse (35104035321), we get a palindrome (47457075474).
The spelling of 12353040153 in words is "twelve billion, three hundred fifty-three million, forty thousand, one hundred fifty-three".
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