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12353040153 = 323316436449
BaseRepresentation
bin10111000000100110…
…00110111100011001
31011212220102110101200
423200103012330121
5200244334241103
65401440304413
7615056052216
oct134023067431
934786373350
1012353040153
115269a729a3
122489012109
13121b34371c
1485287ab0d
154c475a0a3
hex2e04c6f19

12353040153 has 24 divisors (see below), whose sum is σ = 17927800800. Its totient is φ = 8196439680.

The previous prime is 12353040143. The next prime is 12353040179. The reversal of 12353040153 is 35104035321.

12353040153 is a `hidden beast` number, since 123 + 530 + 4 + 0 + 1 + 5 + 3 = 666.

It is not a de Polignac number, because 12353040153 - 25 = 12353040121 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12353040103) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1912273 + ... + 1918721.

It is an arithmetic number, because the mean of its divisors is an integer number (746991700).

Almost surely, 212353040153 is an apocalyptic number.

It is an amenable number.

12353040153 is a deficient number, since it is larger than the sum of its proper divisors (5574760647).

12353040153 is a wasteful number, since it uses less digits than its factorization.

12353040153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7429 (or 7426 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 12353040153 its reverse (35104035321), we get a palindrome (47457075474).

The spelling of 12353040153 in words is "twelve billion, three hundred fifty-three million, forty thousand, one hundred fifty-three".

Divisors: 1 3 9 331 643 993 1929 2979 5787 6449 19347 58041 212833 638499 1915497 2134619 4146707 6403857 12440121 19211571 37320363 1372560017 4117680051 12353040153