Base | Representation |
---|---|
bin | 1011001111000010101010… |
… | …1101000111111011010001 |
3 | 1121201221100202200000101001 |
4 | 2303300222231013323101 |
5 | 3104343012324242223 |
6 | 42134524230142001 |
7 | 2413322623021165 |
oct | 263605255077321 |
9 | 47657322600331 |
10 | 12353042415313 |
11 | 3a32994444876 |
12 | 1476128ab1901 |
13 | 6b7b6b6a3752 |
14 | 309c67538ca5 |
15 | 1664e70e59ad |
hex | b3c2ab47ed1 |
12353042415313 has 4 divisors (see below), whose sum is σ = 12353774637888. Its totient is φ = 12352310192740.
The previous prime is 12353042415271. The next prime is 12353042415317. The reversal of 12353042415313 is 31351424035321.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12353042415313 - 221 = 12353040318161 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12353042415317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366085981 + ... + 366119722.
It is an arithmetic number, because the mean of its divisors is an integer number (3088443659472).
Almost surely, 212353042415313 is an apocalyptic number.
It is an amenable number.
12353042415313 is a deficient number, since it is larger than the sum of its proper divisors (732222575).
12353042415313 is an equidigital number, since it uses as much as digits as its factorization.
12353042415313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 732222574.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 12353042415313 in words is "twelve trillion, three hundred fifty-three billion, forty-two million, four hundred fifteen thousand, three hundred thirteen".
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