Base | Representation |
---|---|
bin | 11100000101100111001110… |
… | …101010000011011111011111 |
3 | 121012101110011021202002020111 |
4 | 130011213032222003133133 |
5 | 112142413013002443403 |
6 | 1114421211242430451 |
7 | 35006551605034354 |
oct | 3405471652033737 |
9 | 535343137662214 |
10 | 123531021531103 |
11 | 363a723723089a |
12 | 11a31181202427 |
13 | 53c0c04ca7bb4 |
14 | 2270d0d14862b |
15 | e434d313c56d |
hex | 7059cea837df |
123531021531103 has 2 divisors, whose sum is σ = 123531021531104. Its totient is φ = 123531021531102.
The previous prime is 123531021531091. The next prime is 123531021531107. The reversal of 123531021531103 is 301135120135321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123531021531103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123531021531107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61765510765551 + 61765510765552.
It is an arithmetic number, because the mean of its divisors is an integer number (61765510765552).
Almost surely, 2123531021531103 is an apocalyptic number.
123531021531103 is a deficient number, since it is larger than the sum of its proper divisors (1).
123531021531103 is an equidigital number, since it uses as much as digits as its factorization.
123531021531103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 123531021531103 its reverse (301135120135321), we get a palindrome (424666141666424).
The spelling of 123531021531103 in words is "one hundred twenty-three trillion, five hundred thirty-one billion, twenty-one million, five hundred thirty-one thousand, one hundred three".
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