Base | Representation |
---|---|
bin | 1011001111000011101011… |
… | …0010011011110111000111 |
3 | 1121201222001120101200120101 |
4 | 2303300322302123313013 |
5 | 3104344040413240033 |
6 | 42135011105344531 |
7 | 2413332410354224 |
oct | 263607262336707 |
9 | 47658046350511 |
10 | 12353312243143 |
11 | 3a33012790483 |
12 | 14761a3338147 |
13 | 6b7bb25690a1 |
14 | 309c912d694b |
15 | 166510b4497d |
hex | b3c3ac9bdc7 |
12353312243143 has 2 divisors, whose sum is σ = 12353312243144. Its totient is φ = 12353312243142.
The previous prime is 12353312243101. The next prime is 12353312243197. The reversal of 12353312243143 is 34134221335321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12353312243143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12353312243443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6176656121571 + 6176656121572.
It is an arithmetic number, because the mean of its divisors is an integer number (6176656121572).
Almost surely, 212353312243143 is an apocalyptic number.
12353312243143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12353312243143 is an equidigital number, since it uses as much as digits as its factorization.
12353312243143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 37.
Adding to 12353312243143 its reverse (34134221335321), we get a palindrome (46487533578464).
The spelling of 12353312243143 in words is "twelve trillion, three hundred fifty-three billion, three hundred twelve million, two hundred forty-three thousand, one hundred forty-three".
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