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123534452047 is a prime number
BaseRepresentation
bin111001100001100111…
…0100010010101001111
3102210212022212101012211
41303003032202111033
54010444304431142
6132430112011251
711632204342216
oct1630316422517
9383768771184
10123534452047
1148432a83276
121bb37530b27
13b859527206
145d9c91207d
15333041a917
hex1cc33a254f

123534452047 has 2 divisors, whose sum is σ = 123534452048. Its totient is φ = 123534452046.

The previous prime is 123534452009. The next prime is 123534452051. The reversal of 123534452047 is 740254435321.

It is a strong prime.

It is an emirp because it is prime and its reverse (740254435321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123534452047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123534453047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61767226023 + 61767226024.

It is an arithmetic number, because the mean of its divisors is an integer number (61767226024).

Almost surely, 2123534452047 is an apocalyptic number.

123534452047 is a deficient number, since it is larger than the sum of its proper divisors (1).

123534452047 is an equidigital number, since it uses as much as digits as its factorization.

123534452047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 40.

Adding to 123534452047 its reverse (740254435321), we get a palindrome (863788887368).

The spelling of 123534452047 in words is "one hundred twenty-three billion, five hundred thirty-four million, four hundred fifty-two thousand, forty-seven".