Base | Representation |
---|---|
bin | 1011001111000110011100… |
… | …0001001101100010010100 |
3 | 1121202000222021201210121002 |
4 | 2303301213001031202110 |
5 | 3104402100401023012 |
6 | 42135212454442432 |
7 | 2413356661020416 |
oct | 263614701154224 |
9 | 47660867653532 |
10 | 12354054314132 |
11 | 3a33363655393 |
12 | 147636b963418 |
13 | 6b7ca021884b |
14 | 309d21aa29b6 |
15 | 166555d777c2 |
hex | b3c6704d894 |
12354054314132 has 6 divisors (see below), whose sum is σ = 21619595049738. Its totient is φ = 6177027157064.
The previous prime is 12354054314051. The next prime is 12354054314137. The reversal of 12354054314132 is 23141345045321.
It can be written as a sum of positive squares in only one way, i.e., 8803528121476 + 3550526192656 = 2967074^2 + 1884284^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12354054314137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1544256789263 + ... + 1544256789270.
It is an arithmetic number, because the mean of its divisors is an integer number (3603265841623).
Almost surely, 212354054314132 is an apocalyptic number.
It is an amenable number.
12354054314132 is a deficient number, since it is larger than the sum of its proper divisors (9265540735606).
12354054314132 is a wasteful number, since it uses less digits than its factorization.
12354054314132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3088513578537 (or 3088513578535 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 12354054314132 its reverse (23141345045321), we get a palindrome (35495399359453).
The spelling of 12354054314132 in words is "twelve trillion, three hundred fifty-four billion, fifty-four million, three hundred fourteen thousand, one hundred thirty-two".
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