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12354544505593 is a prime number
BaseRepresentation
bin1011001111001000010000…
…1111001001001011111001
31121202002020110010002212101
42303302010033021023321
53104404101343134333
642135333245143401
72413405062413143
oct263620417111371
947662213102771
1012354544505593
113a335953224a4
121476487b5ab61
136b804a948274
14309d6ac23c93
15166583e0467d
hexb3c843c92f9

12354544505593 has 2 divisors, whose sum is σ = 12354544505594. Its totient is φ = 12354544505592.

The previous prime is 12354544505591. The next prime is 12354544505609. The reversal of 12354544505593 is 39550544545321.

12354544505593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11348220538944 + 1006323966649 = 3368712^2 + 1003157^2 .

It is a cyclic number.

It is not a de Polignac number, because 12354544505593 - 21 = 12354544505591 is a prime.

Together with 12354544505591, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12354544505591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6177272252796 + 6177272252797.

It is an arithmetic number, because the mean of its divisors is an integer number (6177272252797).

Almost surely, 212354544505593 is an apocalyptic number.

It is an amenable number.

12354544505593 is a deficient number, since it is larger than the sum of its proper divisors (1).

12354544505593 is an equidigital number, since it uses as much as digits as its factorization.

12354544505593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400000, while the sum is 55.

The spelling of 12354544505593 in words is "twelve trillion, three hundred fifty-four billion, five hundred forty-four million, five hundred five thousand, five hundred ninety-three".